What is the vertices (x^2)/(100)+(y^2)/(44)=1 ?

The vertices (x^2)/(100)+(y^2)/(44)=1 is (10,0),(-10,0)

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vertices (x^2)/(100)+(y^2)/(44)=1

vertices

\frac{x ^{2}}{100} + \frac{y ^{2}}{44} = 1

(10, 0), (- 10, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate ellipse properties

\frac{x ^{2}}{100} + \frac{y ^{2}}{44} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 10, b = 211

(0 + 10, 0), (0 - 10, 0)

Refine

(10, 0), (- 10, 0)

\frac{x ^{2}}{36} + \frac{( y + 1 ) ^{2}}{25} = 1

25 x^{2} + 144 y^{2} = 900

4 x^{2} + 16 y^{2} - 16 x - 48 = 0

25 (x + 2)^{2} + 4 (y - 3)^{2} = 100

4 x^{2} + y^{2} + 6 y + 5 = 0

What is the vertices (x^2)/(100)+(y^2)/(44)=1 ?
The vertices (x^2)/(100)+(y^2)/(44)=1 is (10,0),(-10,0)