What is the vertices 4x^2+9y^2+32x-18y+37=0 ?

The vertices 4x^2+9y^2+32x-18y+37=0 is (-1,1),(-7,1)

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vertices 4x^2+9y^2+32x-18y+37=0

vertices

4 x^{2} + 9 y^{2} + 32 x - 18 y + 37 = 0

(- 1, 1), (- 7, 1)

Solution steps

(h + a, k), (h - a, k)

Calculate ellipse properties

4 x^{2} + 9 y^{2} + 32 x - 18 y + 37 = 0 :

Ellipse with center

(h, k) = (- 4, 1), a = 3, b = 2

(- 4 + 3, 1), (- 4 - 3, 1)

Refine

(- 1, 1), (- 7, 1)

\frac{( x + 1 ) ^{2}}{3} + \frac{( y - 1 ) ^{2}}{6} = 4

(x + 3)^{2} + y^{2} = 36

16 x^{2} + 25 y^{2} - 64 x + 150 y - 111 = 0

9 x^{2} + 16 y^{2} - 36 x + 96 y + 36 = 0

\frac{x ^{2}}{25} + \frac{y ^{2}}{36} = 1

What is the vertices 4x^2+9y^2+32x-18y+37=0 ?
The vertices 4x^2+9y^2+32x-18y+37=0 is (-1,1),(-7,1)