What is the vertices 9x^2+49y^2-144x+490y+1360=0 ?

The vertices 9x^2+49y^2-144x+490y+1360=0 is (15,-5),(1,-5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

vertices 9x^2+49y^2-144x+490y+1360=0

vertices

9 x^{2} + 49 y^{2} - 144 x + 490 y + 1360 = 0

(15, - 5), (1, - 5)

Solution steps

(h + a, k), (h - a, k)

Calculate ellipse properties

9 x^{2} + 49 y^{2} - 144 x + 490 y + 1360 = 0 :

Ellipse with center

(h, k) = (8, - 5), a = 7, b = 3

(8 + 7, - 5), (8 - 7, - 5)

Refine

(15, - 5), (1, - 5)

4 x^{2} + 9 y^{2} - 24 x + 72 y + 144 = 0

16 x^{2} + 25 y^{2} = 400

\frac{x ^{2}}{4} + y^{2} = 1

9 x^{2} + 4 y^{2} + 18 x - 8 y - 131 = 0

25 x^{2} - 200 x + y^{2} + 4 y + 379 = 0

What is the vertices 9x^2+49y^2-144x+490y+1360=0 ?
The vertices 9x^2+49y^2-144x+490y+1360=0 is (15,-5),(1,-5)