What is (x/(16))^2+(y^2)/(81)=1 ?

The solution to (x/(16))^2+(y^2)/(81)=1 is Ellipse with (h,k)=(0,0),a=16,b=9

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(x/(16))^2+(y^2)/(81)=1

(\frac{x}{16})^{2} + \frac{y ^{2}}{81} = 1

(h, k) = (0, 0), a = 16, b = 9

Solution steps

(\frac{x}{16})^{2} + \frac{y ^{2}}{81} = 1

Rewrite

(\frac{x}{16})^{2} + \frac{y ^{2}}{81} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{1 6 ^{2}} + \frac{( y - 0 ) ^{2}}{9 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 16, b = 9

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 16, b = 9

11 x^{2} + 5 y^{2} + 110 x - 20 y + 240 = 0

\frac{x ^{2}}{cosh ^{2} ( β )} + \frac{y ^{2}}{sinh ^{2} ( β )} = 1

4 x^{2} = 36 - 9 y^{2}

\frac{( x + 2 ) ^{2}}{25} + \frac{( y - 1 ) ^{2}}{16} = 1

25 x^{2} + 16 y^{2} + 100 x - 96 y - 154 = 0

What is (x/(16))^2+(y^2)/(81)=1 ?
The solution to (x/(16))^2+(y^2)/(81)=1 is Ellipse with (h,k)=(0,0),a=16,b=9