What is (x^2)/(5800^2)+(y^2)/(1500^2)=1 ?

The solution to (x^2)/(5800^2)+(y^2)/(1500^2)=1 is Ellipse with (h,k)=(0,0),a=5800,b=1500

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(x^2)/(5800^2)+(y^2)/(1500^2)=1

\frac{x ^{2}}{580 0 ^{2}} + \frac{y ^{2}}{150 0 ^{2}} = 1

(h, k) = (0, 0), a = 5800, b = 1500

Solution steps

\frac{x ^{2}}{580 0 ^{2}} + \frac{y ^{2}}{150 0 ^{2}} = 1

Rewrite

\frac{x ^{2}}{580 0 ^{2}} + \frac{y ^{2}}{150 0 ^{2}} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{580 0 ^{2}} + \frac{( y - 0 ) ^{2}}{150 0 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 5800, b = 1500

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 5800, b = 1500

9 x^{2} + y^{2} - 54 x - 6 y + 81 = 0

x^{2} = \frac{4 - y ^{2}}{2}

64 x^{2} - 192 x - 156 + 100 y^{2} - 200 y = 0

\frac{( x - 3 ) ^{2}}{64} + \frac{( y + 4 ) ^{2}}{81} = 1

49 x^{2} + 4 y^{2} + 98 x - 147 = 0

What is (x^2)/(5800^2)+(y^2)/(1500^2)=1 ?
The solution to (x^2)/(5800^2)+(y^2)/(1500^2)=1 is Ellipse with (h,k)=(0,0),a=5800,b=1500