What is x/((x^2){64}+\frac{y^2)/9}=1 ?

The solution to x/((x^2){64}+\frac{y^2)/9}=1 is Ellipse with (h,k)=(32,0),a=32,b=12

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x/((x^2){64}+\frac{y^2)/9}=1

\frac{x}{\frac{x ^{2}}{64} + \frac{y ^{2}}{9}} = 1

(h, k) = (32, 0), a = 32, b = 12

Solution steps

\frac{x}{\frac{x ^{2}}{64} + \frac{y ^{2}}{9}} = 1

Rewrite

\frac{x}{\frac{x ^{2}}{64} + \frac{y ^{2}}{9}} = 1

in the form of the standard ellipse equation

\frac{( x - 32 ) ^{2}}{3 2 ^{2}} + \frac{( y - 0 ) ^{2}}{1 2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (32, 0), a = 32, b = 12

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (32, 0), a = 32, b = 12

y^{2} + 2 x^{2} = 4

x^{2} + \frac{1}{4} y^{2} = x + y

\frac{( x - 2 ) ^{2}}{1 ^{2}} + \frac{( y + 1 ) ^{2}}{2} = 1

\frac{x ^{2}}{( 1 ) ^{2}} + \frac{y ^{2}}{( \frac{1}{2} ) ^{2}} = 2

\frac{x ^{2}}{( 1 ) ^{2}} + \frac{y ^{2}}{( \frac{1}{2} ) ^{2}} = 1

What is x/((x^2){64}+\frac{y^2)/9}=1 ?
The solution to x/((x^2){64}+\frac{y^2)/9}=1 is Ellipse with (h,k)=(32,0),a=32,b=12