What is (y^2}{16}+\frac{x^2)/4 =1 ?

The solution to (y^2}{16}+\frac{x^2)/4 =1 is Ellipse with (h,k)=(0,0),a=2,b=4

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(y^2}{16}+\frac{x^2)/4 =1

\frac{y ^{2}}{16} + \frac{x ^{2}}{4} = 1

(h, k) = (0, 0), a = 2, b = 4

Solution steps

\frac{y ^{2}}{16} + \frac{x ^{2}}{4} = 1

Rewrite

\frac{y ^{2}}{16} + \frac{x ^{2}}{4} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} + \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 2, b = 4

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 4, a = 2

12 x^{2} + 8 y^{2} = 96

10 x^{2} + 3 y^{2} = 30

\frac{x ^{2}}{k} + \frac{y ^{2}}{4 + k} = 1

\frac{( x + 1 ) ^{2}}{64} + \frac{( y - 5 ) ^{2}}{9} = 1

\frac{( ( x - 4 ) ^{2} )}{36} + \frac{( ( y - 2 ) ^{2} )}{9} = 1

What is (y^2}{16}+\frac{x^2)/4 =1 ?
The solution to (y^2}{16}+\frac{x^2)/4 =1 is Ellipse with (h,k)=(0,0),a=2,b=4