What is 3x^2+y^2-12=0 ?

The solution to 3x^2+y^2-12=0 is Ellipse with (h,k)=(0,0),a=2,b=2sqrt(3)

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3x^2+y^2-12=0

3 x^{2} + y^{2} - 12 = 0

(h, k) = (0, 0), a = 2, b = 23

Solution steps

3 x^{2} + y^{2} - 12 = 0

Rewrite

3 x^{2} + y^{2} - 12 = 0

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} + \frac{( y - 0 ) ^{2}}{( 2 3 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 2, b = 23

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 23, a = 2

4 y^{2} + x^{2} - 2 x = 3

\frac{( x ) ^{2}}{49} + \frac{( y ) ^{2}}{25} = 1

\frac{( - y )}{- 2 - x} = \frac{( - 1 )}{\frac{( 4 - y )}{6 - x}}

9 (x + 9)^{2} + 4 (y - 12)^{2} = 1284

(x - 4)^{2} + y^{2} = \frac{1}{4} ((x + 2)^{2} + (y - y))

What is 3x^2+y^2-12=0 ?
The solution to 3x^2+y^2-12=0 is Ellipse with (h,k)=(0,0),a=2,b=2sqrt(3)