What is ((x-1)^2)/9+((y+5)^2)/(16)=1 ?

The solution to ((x-1)^2)/9+((y+5)^2)/(16)=1 is Ellipse with (h,k)=(1,-5),a=3,b=4

Popular >

((x-1)^2)/9+((y+5)^2)/(16)=1

\frac{( x - 1 ) ^{2}}{9} + \frac{( y + 5 ) ^{2}}{16} = 1

(h, k) = (1, - 5), a = 3, b = 4

Solution steps

\frac{( x - 1 ) ^{2}}{9} + \frac{( y + 5 ) ^{2}}{16} = 1

Rewrite

\frac{( x - 1 ) ^{2}}{9} + \frac{( y + 5 ) ^{2}}{16} = 1

in the form of the standard ellipse equation

\frac{( x - 1 ) ^{2}}{3 ^{2}} + \frac{( y - ( - 5 ) ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (1, - 5), a = 3, b = 4

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (1, - 5), b = 4, a = 3

\frac{( x - 18.093 ) ^{2}}{20} + \frac{( y - 3 ) ^{2}}{21} = 1

\frac{( x - 20 ) ^{2}}{4} + \frac{( y + 1 ) ^{2}}{9} = 1

\frac{( x + 1 ) ^{2}}{2} + \frac{( y - 6 ) ^{2}}{187} = 1

x^{2} + 5 y^{2} - 6 x + 20 y = - 24

\frac{( x - 1 ) ^{2}}{425} + \frac{( y - 2 ) ^{2}}{400} = 1

What is ((x-1)^2)/9+((y+5)^2)/(16)=1 ?
The solution to ((x-1)^2)/9+((y+5)^2)/(16)=1 is Ellipse with (h,k)=(1,-5),a=3,b=4