What is (x^2)/4+(y^2)/7 =1 ?

The solution to (x^2)/4+(y^2)/7 =1 is Ellipse with (h,k)=(0,0),a=2,b=sqrt(7)

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(x^2)/4+(y^2)/7 =1

\frac{x ^{2}}{4} + \frac{y ^{2}}{7} = 1

(h, k) = (0, 0), a = 2, b = 7

Solution steps

\frac{x ^{2}}{4} + \frac{y ^{2}}{7} = 1

Rewrite

\frac{x ^{2}}{4} + \frac{y ^{2}}{7} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} + \frac{( y - 0 ) ^{2}}{( 7 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 2, b = 7

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 7, a = 2

16 x^{2} + 9 y^{2} + 160 x - 72 y + 544 = 144

\frac{( x - 2 ) ^{2}}{9} + \frac{( y + 3 ) ^{2}}{4} = 1

7 x^{2} + 18 y^{2} = 63

\frac{( x + 3 ) ^{2}}{100} + \frac{( y + 4 ) ^{2}}{32} = 1

\frac{x ^{2}}{7} + \frac{y ^{2}}{4} = 1

What is (x^2)/4+(y^2)/7 =1 ?
The solution to (x^2)/4+(y^2)/7 =1 is Ellipse with (h,k)=(0,0),a=2,b=sqrt(7)