What is (x^2)/9+(z^2)/(49)=1 ?

The solution to (x^2)/9+(z^2)/(49)=1 is Ellipse with (h,k)=(0,0),a=3,b=7

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(x^2)/9+(z^2)/(49)=1

\frac{x ^{2}}{9} + \frac{z ^{2}}{49} = 1

(h, k) = (0, 0), a = 3, b = 7

Solution steps

\frac{x ^{2}}{9} + \frac{z ^{2}}{49} = 1

Rewrite

\frac{x ^{2}}{9} + \frac{z ^{2}}{49} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{3 ^{2}} + \frac{( z - 0 ) ^{2}}{7 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 3, b = 7

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 7, a = 3

x^{2} + 2 x + 4 y^{2} - 16 y + 1 = 0

\frac{( x - 1 ) ^{2}}{0. 1 ^{2}} + \frac{( y - 1 ) ^{2}}{0. 5 ^{2}} = 1

x^{2} + 2 y^{2} + 5 x - 2 y - 1 = 0

\frac{( x ^{2} )}{16} + \frac{( y ^{2} )}{25} = 1

(\frac{x ^{2}}{9}) + (\frac{y ^{2}}{16}) = 1

What is (x^2)/9+(z^2)/(49)=1 ?
The solution to (x^2)/9+(z^2)/(49)=1 is Ellipse with (h,k)=(0,0),a=3,b=7