What is (x^2)/(36)+(8y^2)/(81)=1 ?

The solution to (x^2)/(36)+(8y^2)/(81)=1 is Ellipse with (h,k)=(0,0),a=6,b= 9/(2sqrt(2))

Popular >

(x^2)/(36)+(8y^2)/(81)=1

\frac{x ^{2}}{36} + \frac{8 y ^{2}}{81} = 1

(h, k) = (0, 0), a = 6, b = \frac{9}{2 2}

Solution steps

\frac{x ^{2}}{36} + \frac{8 y ^{2}}{81} = 1

Rewrite

\frac{x ^{2}}{36} + \frac{8 y ^{2}}{81} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{6 ^{2}} + \frac{( y - 0 ) ^{2}}{( \frac{9}{2 2} ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 6, b = \frac{9}{2 2}

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 6, b = \frac{9}{2 2}

3 x^{2} + 7 y^{2} = 1

4 x^{2} + 9 y^{2} - 16 x - 36 y + 16 = 0

\frac{( x + 2 ) ^{2}}{36} + \frac{( y + 1 ) ^{2}}{25} = 1

4 x^{2} + 7 y^{2} = 1

\frac{( x - 3 ) ^{2}}{16} + \frac{( y - 1 ) ^{2}}{4} = 1

What is (x^2)/(36)+(8y^2)/(81)=1 ?
The solution to (x^2)/(36)+(8y^2)/(81)=1 is Ellipse with (h,k)=(0,0),a=6,b= 9/(2sqrt(2))