What is (X/(16))^2+((Y+1)^2)/4-1=0 ?

The solution to (X/(16))^2+((Y+1)^2)/4-1=0 is Ellipse with (h,k)=(0,-1),a=16,b=2

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(X/(16))^2+((Y+1)^2)/4-1=0

(\frac{X}{16})^{2} + \frac{( Y + 1 ) ^{2}}{4} - 1 = 0

(h, k) = (0, - 1), a = 16, b = 2

Solution steps

(\frac{X}{16})^{2} + \frac{( Y + 1 ) ^{2}}{4} - 1 = 0

Rewrite

(\frac{X}{16})^{2} + \frac{( Y + 1 ) ^{2}}{4} - 1 = 0

in the form of the standard ellipse equation

\frac{( X - 0 ) ^{2}}{1 6 ^{2}} + \frac{( Y - ( - 1 ) ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, - 1), a = 16, b = 2

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, - 1), a = 16, b = 2

\frac{( x - 0 ) ^{2}}{4} + \frac{( y - 0 ) ^{2}}{16} = 1

\frac{( x + 2 ) ^{2}}{25} + \frac{( y - 1 ) ^{2}}{9} = 1

25 x^{2} + 16 y^{2} + 100 x - 96 y = 156

x^{2} + 9 y^{2} - 8 x + 36 y + 4 = 0

(\frac{x - 2}{4 ^{2}})^{2} + (\frac{y - 4}{5 ^{2}})^{2} = 1

What is (X/(16))^2+((Y+1)^2)/4-1=0 ?
The solution to (X/(16))^2+((Y+1)^2)/4-1=0 is Ellipse with (h,k)=(0,-1),a=16,b=2