What is (x^2}{20}+\frac{y^2)/4 =1 ?

The solution to (x^2}{20}+\frac{y^2)/4 =1 is Ellipse with (h,k)=(0,0),a=2sqrt(5),b=2

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(x^2}{20}+\frac{y^2)/4 =1

\frac{x ^{2}}{20} + \frac{y ^{2}}{4} = 1

(h, k) = (0, 0), a = 25, b = 2

Solution steps

\frac{x ^{2}}{20} + \frac{y ^{2}}{4} = 1

Rewrite

\frac{x ^{2}}{20} + \frac{y ^{2}}{4} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( 2 5 ) ^{2}} + \frac{( y - 0 ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 25, b = 2

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 25, b = 2

\frac{x ^{2}}{100} + \frac{y ^{2}}{16} = 1

4 x^{2} + 16 y^{2} - 16 x - 48 = 0

50 y^{2} + 18 x^{2} - 200 y + 36 x - 232 = 0

3 x^{2} + 2 y^{2} + 6 x - 8 y - 25 = 0

\frac{x ^{2}}{6 ^{2}} + \frac{y ^{2}}{3 ^{2}} = 1

What is (x^2}{20}+\frac{y^2)/4 =1 ?
The solution to (x^2}{20}+\frac{y^2)/4 =1 is Ellipse with (h,k)=(0,0),a=2sqrt(5),b=2