What is (x^2)/(8^2)+(y^2)/(4^2)=1 ?

The solution to (x^2)/(8^2)+(y^2)/(4^2)=1 is Ellipse with (h,k)=(0,0),a=8,b=4

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(x^2)/(8^2)+(y^2)/(4^2)=1

\frac{x ^{2}}{8 ^{2}} + \frac{y ^{2}}{4 ^{2}} = 1

(h, k) = (0, 0), a = 8, b = 4

Solution steps

\frac{x ^{2}}{8 ^{2}} + \frac{y ^{2}}{4 ^{2}} = 1

Rewrite

\frac{x ^{2}}{8 ^{2}} + \frac{y ^{2}}{4 ^{2}} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{8 ^{2}} + \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 8, b = 4

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 8, b = 4

28 - 4 x^{2} - 7 y^{2} > 0

2 x^{2} + y^{2} - 2 x + 4 y = 2

\frac{( x - 1 ) ^{2}}{4} + \frac{( y - 3 ) ^{2}}{9} = 1

x^{2} + 8 y^{2} = 32

\frac{( x - 1 ) ^{2}}{5 ^{2}} + \frac{( y + 1 ) ^{2}}{3 ^{2}} = 1

What is (x^2)/(8^2)+(y^2)/(4^2)=1 ?
The solution to (x^2)/(8^2)+(y^2)/(4^2)=1 is Ellipse with (h,k)=(0,0),a=8,b=4