What is the circle, find Area, given r=c:(2,-1)r=3 ?

The circle, find Area, given r=c:(2,-1)r=3 is A=pi(3cr:=(2,-1))^2

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circle, find Area, given r=c:(2,-1)r=3

circle, find Area, given r=c:\left(2, -1\right)r=3

A = π (3 cr := (2, - 1))^{2}

Solution steps

A = π r^{2}

r = c : (2, - 1) r = 3

A = π (3 cr := (2, - 1))^{2}

x^{2} + y^{2} - 12 y + 32 = 0

x^{2} + y^{2} = 20

x^{2} + y^{2} < 1

(x + 40)^{2} + y^{2} = 30

x^{2} + y^{2} - 2 x + 6 y - 15 = 0

What is the circle, find Area, given r=c:(2,-1)r=3 ?
The circle, find Area, given r=c:(2,-1)r=3 is A=pi(3cr:=(2,-1))^2