en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area x^2+y^2-4x=0

Solution

area

x^{2} + y^{2} - 4 x = 0

Solution

A = 4 π

Solution steps

A = π r^{2}

Find the radius

Radius given

x^{2} + y^{2} - 4 x = 0 : r = 2

A = π 2^{2}

Refine

A = 4 π

Popular Examples

area x^2+y^2= 25/36 area

x^{2} + y^{2} = \frac{25}{36}

area x^2+y^2-2x+6y+9=0 area

x^{2} + y^{2} - 2 x + 6 y + 9 = 0

area (x-2)^2+y^2=16 area

(x - 2)^{2} + y^{2} = 16

area x^2+y^2-25=0 area

x^{2} + y^{2} - 25 = 0

area y^2=4-x^2 area

y^{2} = 4 - x^{2}

Frequently Asked Questions (FAQ)

What is the area x^2+y^2-4x=0 ?
The area x^2+y^2-4x=0 is A=4pi