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Popular >

area 2x^2+2y^2-2x-2y-3=0

Solution

area

2 x^{2} + 2 y^{2} - 2 x - 2 y - 3 = 0

Solution

A = 2 π

Solution steps

A = π r^{2}

Find the radius

Radius given

2 x^{2} + 2 y^{2} - 2 x - 2 y - 3 = 0 : r = 2

A = π (2)^{2}

Refine

A = 2 π

Popular Examples

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x^{2} + y^{2} = 8

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x^{2} + y^{2} \leq 16

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area x^2+y^2= 7/pi area

x^{2} + y^{2} = \frac{7}{π}

Frequently Asked Questions (FAQ)

What is the area 2x^2+2y^2-2x-2y-3=0 ?
The area 2x^2+2y^2-2x-2y-3=0 is A=2pi