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Popular >

area 3x^2+3y^2+2x-4y-1=0

Solution

area

3 x^{2} + 3 y^{2} + 2 x - 4 y - 1 = 0

Solution

A = \frac{8 π}{9}

Solution steps

A = π r^{2}

Find the radius

Radius given

3 x^{2} + 3 y^{2} + 2 x - 4 y - 1 = 0 : r = \frac{2 2}{3}

A = π (\frac{2 2}{3})^{2}

Refine

A = \frac{8 π}{9}

Popular Examples

area x^2+y^2-2x+4y-31=0 area

x^{2} + y^{2} - 2 x + 4 y - 31 = 0

area 4x^2+4y^2-4x+2y-1=0 area

4 x^{2} + 4 y^{2} - 4 x + 2 y - 1 = 0

area x^2+y^2=4 area

x^{2} + y^{2} = 4

area (x+4)^2+(y-6)^2=18 area

(x + 4)^{2} + (y - 6)^{2} = 18

area+x^2+y^2=4 area

+ x^{2} + y^{2} = 4

Frequently Asked Questions (FAQ)

What is the area 3x^2+3y^2+2x-4y-1=0 ?
The area 3x^2+3y^2+2x-4y-1=0 is A=(8pi)/9