What is the radius (x-4)^2+(y+1)^2=9 ?

The radius (x-4)^2+(y+1)^2=9 is r=3

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radius (x-4)^2+(y+1)^2=9

radius

(x - 4)^{2} + (y + 1)^{2} = 9

r = 3

Solution steps

(x - 4)^{2} + (y + 1)^{2} = 9

Rewrite

(x - 4)^{2} + (y + 1)^{2} = 9

in the form of the standard circle equation

(x - 4)^{2} + (y - (- 1))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (4, - 1), r = 3

And the radius is:

r = 3

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