What is the radius x^2+y^2-2x+6y+9=0 ?

The radius x^2+y^2-2x+6y+9=0 is r=1

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radius x^2+y^2-2x+6y+9=0

radius

x^{2} + y^{2} - 2 x + 6 y + 9 = 0

r = 1

Solution steps

x^{2} + y^{2} - 2 x + 6 y + 9 = 0

Rewrite

x^{2} + y^{2} - 2 x + 6 y + 9 = 0

in the form of the standard circle equation

(x - 1)^{2} + (y - (- 3))^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (1, - 3), r = 1

And the radius is:

r = 1

y^{2} + x^{2} - 6 y + 5 = 0

x^{2} + (y - 1)^{2} = 4

x^{2} + y^{2} - 2 x + 4 y - 31 = 0

x^{2} + y^{2} + 8 x - 2 y - 19 = 0

x^{2} + y^{2} - 6 x + 4 y + 9 = 0