Solution

center

Solution

Solution steps
Rewrite in the form of the standard circle equation
Therefore the circle properties are:
And the center is:

Popular Examples

center x^2+(y-2)^2=36center center x^2+y^2+2x-4y+4=0center center 4x^2+4y^2+36y+5=0center center (x)^2+(y-3/2)^2=4center center x^2+y^2-18x+8y+81=0center

Frequently Asked Questions (FAQ)

  • What is the center x^2+y^2-64=0 ?

    The center x^2+y^2-64=0 is (0,0)