What is the center x^2+(y-1)^2=64 ?

The center x^2+(y-1)^2=64 is (0,1)

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center x^2+(y-1)^2=64

center

x^{2} + (y - 1)^{2} = 64

(0, 1)

Solution steps

x^{2} + (y - 1)^{2} = 64

Rewrite

x^{2} + (y - 1)^{2} = 64

in the form of the standard circle equation

(x - 0)^{2} + (y - 1)^{2} = 8^{2}

Therefore the circle properties are:

(a, b) = (0, 1), r = 8

And the center is:

(0, 1)

x^{2} - 10 x + y^{2} + 6 y - 1 = 0

x^{2} + y^{2} - 4 x + 10 y + 20 = 0

x^{2} + y^{2} - 7 x = 36 - 4 y

4 x^{2} + 4 y^{2} = 9

x^{2} + y^{2} - 10 x + 10 y + 49 = 0