What is the center x^2+(y+5)^2=5 ?

The center x^2+(y+5)^2=5 is (0,-5)

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center x^2+(y+5)^2=5

center

x^{2} + (y + 5)^{2} = 5

(0, - 5)

Solution steps

x^{2} + (y + 5)^{2} = 5

Rewrite

x^{2} + (y + 5)^{2} = 5

in the form of the standard circle equation

(x - 0)^{2} + (y - (- 5))^{2} = (5)^{2}

Therefore the circle properties are:

(a, b) = (0, - 5), r = 5

And the center is:

(0, - 5)

2 x^{2} + 2 y^{2} + 16 x - 32 y + 134 = 0

(x - 3)^{2} + (y + 4)^{2} = 2

(x - 0)^{2} + (y - 0)^{2} = 4

x^{2} + y^{2} + 10 x - 16 y + 75 = 0

- 20 - x^{2} = - 16 x - 20 y + y^{2}