What is the center x^2+5x+y^2-y= 5/2 ?

The center x^2+5x+y^2-y= 5/2 is (-5/2 , 1/2)

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center x^2+5x+y^2-y= 5/2

center

x^{2} + 5 x + y^{2} - y = \frac{5}{2}

(- \frac{5}{2}, \frac{1}{2})

Solution steps

x^{2} + 5 x + y^{2} - y = \frac{5}{2}

Rewrite

x^{2} + 5 x + y^{2} - y = \frac{5}{2}

in the form of the standard circle equation

(x - (- \frac{5}{2}))^{2} + (y - \frac{1}{2})^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (- \frac{5}{2}, \frac{1}{2}), r = 3

And the center is:

(- \frac{5}{2}, \frac{1}{2})

(x - 4)^{2} + (y + 1)^{2} = 18

(x - 4)^{2} + (y + 1)^{2} = 16

x^{2} + y^{2} - 6 x - 12 y - 55 = 0

x^{2} + y^{2} + 4 x + 2 y - 11 = 0

(x - 2)^{2} + (y - 1)^{2} = 49

What is the center x^2+5x+y^2-y= 5/2 ?
The center x^2+5x+y^2-y= 5/2 is (-5/2 , 1/2)