What is the center (x+11)^2+(y+8)^2=147 ?

The center (x+11)^2+(y+8)^2=147 is (-11,-8)

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center (x+11)^2+(y+8)^2=147

center

(x + 11)^{2} + (y + 8)^{2} = 147

(- 11, - 8)

Solution steps

(x + 11)^{2} + (y + 8)^{2} = 147

Rewrite

(x + 11)^{2} + (y + 8)^{2} = 147

in the form of the standard circle equation

(x - (- 11))^{2} + (y - (- 8))^{2} = (147)^{2}

Therefore the circle properties are:

(a, b) = (- 11, - 8), r = 147

And the center is:

(- 11, - 8)

(x - 5)^{2} + (y - 6)^{2} = 36

(x - 5)^{2} + (y + 7)^{2} = 9

x^{2} + y^{2} - 4 x - 6 y - 23 = 0

x^{2} + y^{2} - x + 2 y + 1 = 0

(x - 2)^{2} + (y - 3)^{2} = 49

What is the center (x+11)^2+(y+8)^2=147 ?
The center (x+11)^2+(y+8)^2=147 is (-11,-8)