What is the center x^2+7x+y^2-10y+6=0 ?

The center x^2+7x+y^2-10y+6=0 is (-7/2 ,5)

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center x^2+7x+y^2-10y+6=0

center

x^{2} + 7 x + y^{2} - 10 y + 6 = 0

(- \frac{7}{2}, 5)

Solution steps

x^{2} + 7 x + y^{2} - 10 y + 6 = 0

Rewrite

x^{2} + 7 x + y^{2} - 10 y + 6 = 0

in the form of the standard circle equation

(x - (- \frac{7}{2}))^{2} + (y - 5)^{2} = (\frac{5 5}{2})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{7}{2}, 5), r = \frac{5 5}{2}

And the center is:

(- \frac{7}{2}, 5)

x^{2} + y^{2} + 2 x - 1 y - 4 = 0

(x - 5)^{2} + (y - 3)^{2} = 64

12 x^{2} + 12 y^{2} - 18 x + 4 y - 5 = 0

(x - 3)^{2} + (y - 4)^{2} = 49

x^{2} + y^{2} - 10 x + 9 y + 1 x = 0

What is the center x^2+7x+y^2-10y+6=0 ?
The center x^2+7x+y^2-10y+6=0 is (-7/2 ,5)