Solution

center

Solution

Solution steps
Rewrite in the form of the standard circle equation
Therefore the circle properties are:
And the center is:

Popular Examples

center x^2+(y+3)^2=81center center x^2+y^2-4x-2y-31=0center center (x-3)^2+(y-2)^2=16center center x^2+y^2-14x+2y+14=0center center x^2+y^2-14x+6y+49=0center

Frequently Asked Questions (FAQ)

  • What is the center x^2+y^2+8x=0 ?

    The center x^2+y^2+8x=0 is (-4,0)