Solution

center

Solution

Solution steps
Rewrite in the form of the standard circle equation
Therefore the circle properties are:
And the center is:

Popular Examples

center x^2+y^2-49=0center center (x+1)^2+(y-2)^2=9center center x^2+y^2+4x-2y-31=0center center 364+28y+y^2+x^2=-26xcenter center x^2+y^2=12center

Frequently Asked Questions (FAQ)

  • What is the center (x+5)^2+(y+1)^2=9 ?

    The center (x+5)^2+(y+1)^2=9 is (-5,-1)