What is the center (x-3/2)^2+(y-3/2)^2= 9/4 ?

The center (x-3/2)^2+(y-3/2)^2= 9/4 is (3/2 , 3/2)

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center (x-3/2)^2+(y-3/2)^2= 9/4

center

(x - \frac{3}{2})^{2} + (y - \frac{3}{2})^{2} = \frac{9}{4}

(\frac{3}{2}, \frac{3}{2})

Solution steps

(x - \frac{3}{2})^{2} + (y - \frac{3}{2})^{2} = \frac{9}{4}

Rewrite

(x - \frac{3}{2})^{2} + (y - \frac{3}{2})^{2} = \frac{9}{4}

in the form of the standard circle equation

(x - \frac{3}{2})^{2} + (y - \frac{3}{2})^{2} = (\frac{3}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{3}{2}, \frac{3}{2}), r = \frac{3}{2}

And the center is:

(\frac{3}{2}, \frac{3}{2})

3 (x - 2)^{2} + 3 y^{2} = 3

2 x^{2} + 2 y^{2} + 6 x - 8 y + 12 = 0

4 x^{2} + 12 x + 4 y^{2} + 16 y - 11 = 0

(x - 3)^{2} + (y - 5)^{2} = 4

x^{2} + 20 x + y^{2} + 16 y = - 20

What is the center (x-3/2)^2+(y-3/2)^2= 9/4 ?
The center (x-3/2)^2+(y-3/2)^2= 9/4 is (3/2 , 3/2)