What is the center x^2+y^2=a^2 ?

The center x^2+y^2=a^2 is (0,0)

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center x^2+y^2=a^2

center

x^{2} + y^{2} = a^{2}

(0, 0)

Solution steps

x^{2} + y^{2} = a^{2}

Rewrite

x^{2} + y^{2} = a^{2}

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = a^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = a

And the center is:

(0, 0)

(x + 2)^{2} + y^{2} = 9

3 x^{2} + 3 y^{2} - 24 x + 6 y - 24 = 0

2 x^{2} + 2 y^{2} + 3 x + 5 y - 4 = 0

(x - 1)^{2} + (y - 2)^{2} = 64

x^{2} + (y - 5)^{2} = 25