Solution
center
Solution
Solution steps
Rewrite in the form of the standard circle equation
Therefore the circle properties are:
And the center is:
Popular Examples
center x^2+y^2-25=0center center (x+2)^2+y^2=25center center 144x^2+144y^2+72x+192y+37=0center center 4x^2+4y^2+40x-32y=5center center 4x^2+4y^2+8x-y=0center
Frequently Asked Questions (FAQ)
What is the center x^2+y^2-12y+32=0 ?
The center x^2+y^2-12y+32=0 is (0,6)