What is the center (x+3)^2+(y-5)^2=5 ?

The center (x+3)^2+(y-5)^2=5 is (-3,5)

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center (x+3)^2+(y-5)^2=5

center

(x + 3)^{2} + (y - 5)^{2} = 5

(- 3, 5)

Solution steps

(x + 3)^{2} + (y - 5)^{2} = 5

Rewrite

(x + 3)^{2} + (y - 5)^{2} = 5

in the form of the standard circle equation

(x - (- 3))^{2} + (y - 5)^{2} = (5)^{2}

Therefore the circle properties are:

(a, b) = (- 3, 5), r = 5

And the center is:

(- 3, 5)

x^{2} + y^{2} + 2 x - 2 y = 3

x^{2} + y^{2} + 4 x + 20 y + 23 = 0

2 x^{2} + 2 y^{2} - 8 x + 16 y - 32 = 0

(x - 3)^{2} + (y + 5)^{2} = 16

x^{2} + y^{2} = 13