What is the center x^2+2x+y^2-35=0 ?

The center x^2+2x+y^2-35=0 is (-1,0)

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center x^2+2x+y^2-35=0

center

x^{2} + 2 x + y^{2} - 35 = 0

(- 1, 0)

Solution steps

x^{2} + 2 x + y^{2} - 35 = 0

Rewrite

x^{2} + 2 x + y^{2} - 35 = 0

in the form of the standard circle equation

(x - (- 1))^{2} + (y - 0)^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (- 1, 0), r = 6

And the center is:

(- 1, 0)

x^{2} + y^{2} - 6 x = 7

x^{2} + y^{2} + 6 x - 4 y - 12 = 0

x^{2} + y^{2} - 14 x + 2 y = - 14

4 x^{2} + 4 y^{2} - 16 x + 40 y + 67 = 0

x^{2} + (y - 3)^{2} = 36