What is the center (x-3)^2+(y+4)^2=25 ?

The center (x-3)^2+(y+4)^2=25 is (3,-4)

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center (x-3)^2+(y+4)^2=25

center

(x - 3)^{2} + (y + 4)^{2} = 25

(3, - 4)

Solution steps

(x - 3)^{2} + (y + 4)^{2} = 25

Rewrite

(x - 3)^{2} + (y + 4)^{2} = 25

in the form of the standard circle equation

(x - 3)^{2} + (y - (- 4))^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (3, - 4), r = 5

And the center is:

(3, - 4)

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