What is x^2+(y+4)^2= 3/5 ?

The solution to x^2+(y+4)^2= 3/5 is Circle with (a,b)=(0,-4),r=sqrt(3/5)

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x^2+(y+4)^2= 3/5

x^{2} + (y + 4)^{2} = \frac{3}{5}

(a, b) = (0, - 4), r = \frac{3}{5}

Solution steps

x^{2} + (y + 4)^{2} = \frac{3}{5}

Rewrite

x^{2} + (y + 4)^{2} = \frac{3}{5}

in the form of the standard circle equation

(x - 0)^{2} + (y - (- 4))^{2} = (\frac{3}{5})^{2}

Therefore the circle properties are:

(a, b) = (0, - 4), r = \frac{3}{5}

(X - 3)^{2} + (Y + 1)^{2} = 6

x^{2} + 4 x = 10 - y^{2}

x^{2} + y^{2} = 6 x + 6 y

x^{2} + y^{2} = 9

x^{2} + y^{2} - 2 x - 6 y - 6 = 0

What is x^2+(y+4)^2= 3/5 ?
The solution to x^2+(y+4)^2= 3/5 is Circle with (a,b)=(0,-4),r=sqrt(3/5)