What is 1/3 x^2+1/3 y^2+2y-15=0 ?

The solution to 1/3 x^2+1/3 y^2+2y-15=0 is Circle with (a,b)=(0,-3),r=3sqrt(6)

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1/3 x^2+1/3 y^2+2y-15=0

\frac{1}{3} x^{2} + \frac{1}{3} y^{2} + 2 y - 15 = 0

(a, b) = (0, - 3), r = 36

Solution steps

\frac{1}{3} x^{2} + \frac{1}{3} y^{2} + 2 y - 15 = 0

Rewrite

\frac{1}{3} x^{2} + \frac{1}{3} y^{2} + 2 y - 15 = 0

in the form of the standard circle equation

(x - 0)^{2} + (y - (- 3))^{2} = (36)^{2}

Therefore the circle properties are:

(a, b) = (0, - 3), r = 36

a^{2} + b^{2} = 81

x^{2} + y^{2} + 520 x + 160 y + 202 = 0

2 x^{2} + 2 y^{2} + 20 x + 8 y + 40 = 0

(x - (- 1))^{2} + (y - 4)^{2} = 2^{2}

x, x^{2} - 6 x + Y (x)^{2} + 4 Y = 36

What is 1/3 x^2+1/3 y^2+2y-15=0 ?
The solution to 1/3 x^2+1/3 y^2+2y-15=0 is Circle with (a,b)=(0,-3),r=3sqrt(6)