What is x^2+y^2-3.11x-10.67y-62.22=0 ?

The solution to x^2+y^2-3.11x-10.67y-62.22=0 is Circle with (a,b)=(1.555,5.335),r=9.64884…

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2+y^2-3.11x-10.67y-62.22=0

x^{2} + y^{2} - 3.11 x - 10.67 y - 62.22 = 0

(a, b) = (1.555, 5.335), r = 9.64884 \dots

Solution steps

x^{2} + y^{2} - 3.11 x - 10.67 y - 62.22 = 0

Rewrite

x^{2} + y^{2} - 3.11 x - 10.67 y - 62.22 = 0

in the form of the standard circle equation

(x - 1.555)^{2} + (y - 5.335)^{2} = 9.64884 \dots^{2}

Therefore the circle properties are:

(a, b) = (1.555, 5.335), r = 9.64884 \dots

x^{2} + y^{2} - 5 x = 12 - 6 y

x^{2} + y^{2} + 8 x - 8 y - 18 = 0

(x + 1)^{2} + (y + 4)^{2} = 100

x^{2} + y^{2} - 13 y + 41 = 0

x^{2} + y^{2} + 2 x - 3 y - 7 = 0

What is x^2+y^2-3.11x-10.67y-62.22=0 ?
The solution to x^2+y^2-3.11x-10.67y-62.22=0 is Circle with (a,b)=(1.555,5.335),r=9.64884…