What is (x+1)^2+(y+4)^2=144 ?

The solution to (x+1)^2+(y+4)^2=144 is Circle with (a,b)=(-1,-4),r=12

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(x+1)^2+(y+4)^2=144

(x + 1)^{2} + (y + 4)^{2} = 144

(a, b) = (- 1, - 4), r = 12

Solution steps

(x + 1)^{2} + (y + 4)^{2} = 144

Rewrite

(x + 1)^{2} + (y + 4)^{2} = 144

in the form of the standard circle equation

(x - (- 1))^{2} + (y - (- 4))^{2} = 1 2^{2}

Therefore the circle properties are:

(a, b) = (- 1, - 4), r = 12

(x - 5)^{2} + (y + 7)^{2} = 100

x^{2} + y^{2} + 12 x + 6 y + 41 = 0

x^{2} + y^{2} - 10 x + 12 y - 2 = 0

3 x^{2} + 3 y^{2} - 24 x + 12 y - 15 = 0

5 x^{2} + 5 y^{2} - 20 x + 10 y + 21 = 0

What is (x+1)^2+(y+4)^2=144 ?
The solution to (x+1)^2+(y+4)^2=144 is Circle with (a,b)=(-1,-4),r=12