What is (X+1)^2+(Y-4)^2=25 ?

The solution to (X+1)^2+(Y-4)^2=25 is Circle with (a,b)=(-1,4),r=5

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(X+1)^2+(Y-4)^2=25

(X + 1)^{2} + (Y - 4)^{2} = 25

(a, b) = (- 1, 4), r = 5

Solution steps

(X + 1)^{2} + (Y - 4)^{2} = 25

Rewrite

(X + 1)^{2} + (Y - 4)^{2} = 25

in the form of the standard circle equation

(X - (- 1))^{2} + (Y - 4)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (- 1, 4), r = 5

2 = 16 - x^{2} - y^{2}

(x - 10)^{2} + (y - 6)^{2} = 1

x^{2} + y^{2} - 18 x + 16 y + 81 = 0

(x + 2)^{2} + y^{2} = 8 y - 7

4 x^{2} + 4 y^{2} + 24 x - 8 y - 41 = 0

What is (X+1)^2+(Y-4)^2=25 ?
The solution to (X+1)^2+(Y-4)^2=25 is Circle with (a,b)=(-1,4),r=5