What is 5(x^2-1.8)+5(y^2-28)+26=0 ?

The solution to 5(x^2-1.8)+5(y^2-28)+26=0 is Circle with (a,b)=(0,0),r=sqrt(123/5)

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5(x^2-1.8)+5(y^2-28)+26=0

5 (x^{2} - 1.8) + 5 (y^{2} - 28) + 26 = 0

(a, b) = (0, 0), r = \frac{123}{5}

Solution steps

5 (x^{2} - 1.8) + 5 (y^{2} - 28) + 26 = 0

Rewrite

5 (x^{2} - 1.8) + 5 (y^{2} - 28) + 26 = 0

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = (\frac{123}{5})^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = \frac{123}{5}

x^{2} + y^{2} + 10 x + 6 y + 18 = 0 x

x^{2} + y^{2} - 2 x - 6 y = - 6

x^{2} - 4 x + y^{2} + 4 y = - 3

x^{2} + y^{2} + 8 x + 4 y - 4 = 0

X^{2} + Y^{2} - 5 X + 4 Y - 46 = 0

What is 5(x^2-1.8)+5(y^2-28)+26=0 ?
The solution to 5(x^2-1.8)+5(y^2-28)+26=0 is Circle with (a,b)=(0,0),r=sqrt(123/5)