What is ((x-1)^2)/(16)+((y+2)^2)/(16)=10 ?

The solution to ((x-1)^2)/(16)+((y+2)^2)/(16)=10 is Circle with (a,b)=(1,-2),r=4sqrt(10)

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((x-1)^2)/(16)+((y+2)^2)/(16)=10

\frac{( x - 1 ) ^{2}}{16} + \frac{( y + 2 ) ^{2}}{16} = 10

(a, b) = (1, - 2), r = 410

Solution steps

\frac{( x - 1 ) ^{2}}{16} + \frac{( y + 2 ) ^{2}}{16} = 10

Rewrite

\frac{( x - 1 ) ^{2}}{16} + \frac{( y + 2 ) ^{2}}{16} = 10

in the form of the standard circle equation

(x - 1)^{2} + (y - (- 2))^{2} = (410)^{2}

Therefore the circle properties are:

(a, b) = (1, - 2), r = 410

(x - 4)^{(2)} + (y - 5)^{(2)} = 49

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x^{2} + y^{2} - 6 x - 4 y - 18 = 0

x^{2} + y^{2} + 2 x - 12 y + 12 = 0

x (x - 5) + (y - 2)^{2} = 0

What is ((x-1)^2)/(16)+((y+2)^2)/(16)=10 ?
The solution to ((x-1)^2)/(16)+((y+2)^2)/(16)=10 is Circle with (a,b)=(1,-2),r=4sqrt(10)