What is x^2+(y+1)^2=10 ?

The solution to x^2+(y+1)^2=10 is Circle with (a,b)=(0,-1),r=sqrt(10)

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x^2+(y+1)^2=10

x^{2} + (y + 1)^{2} = 10

(a, b) = (0, - 1), r = 10

Solution steps

x^{2} + (y + 1)^{2} = 10

Rewrite

x^{2} + (y + 1)^{2} = 10

in the form of the standard circle equation

(x - 0)^{2} + (y - (- 1))^{2} = (10)^{2}

Therefore the circle properties are:

(a, b) = (0, - 1), r = 10

x^{2} + (y + 1)^{2} = 11

(x - 3)^{2} + (y - 5)^{2} + (x + 4)^{2} + (y - 2)^{2} = 30

x^{2} + y^{2} - 5 y - 4 y = 46

(x - 2)^{2} + (y + 1)^{2} - 9 = 0

(x - 1)^{2} + (y - 1)^{2} = 20

What is x^2+(y+1)^2=10 ?
The solution to x^2+(y+1)^2=10 is Circle with (a,b)=(0,-1),r=sqrt(10)