What is (x+1)^2+(y-1)^2=40 ?

The solution to (x+1)^2+(y-1)^2=40 is Circle with (a,b)=(-1,1),r=sqrt(40)

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(x+1)^2+(y-1)^2=40

(x + 1)^{2} + (y - 1)^{2} = 40

(a, b) = (- 1, 1), r = 40

Solution steps

(x + 1)^{2} + (y - 1)^{2} = 40

Rewrite

(x + 1)^{2} + (y - 1)^{2} = 40

in the form of the standard circle equation

(x - (- 1))^{2} + (y - 1)^{2} = (40)^{2}

Therefore the circle properties are:

(a, b) = (- 1, 1), r = 40

(x + 1)^{2} + (y - 3)^{2} - 2 = x + y - 2

25 = (x - 4)^{2} + (y + 1)^{2}

(x + 1)^{2} + (y - 1)^{2} = 36

x^{2} + y^{2} + 6 x + 10 y + 9 = 0

x^{2} + y^{2} - \frac{2}{3} x + \frac{8}{3} y = \frac{19}{9}

What is (x+1)^2+(y-1)^2=40 ?
The solution to (x+1)^2+(y-1)^2=40 is Circle with (a,b)=(-1,1),r=sqrt(40)