What is 3=-6x+4y+x^2+y^2 ?

The solution to 3=-6x+4y+x^2+y^2 is Circle with (a,b)=(3,-2),r=4

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3=-6x+4y+x^2+y^2

3 = - 6 x + 4 y + x^{2} + y^{2}

(a, b) = (3, - 2), r = 4

Solution steps

3 = - 6 x + 4 y + x^{2} + y^{2}

Rewrite

3 = - 6 x + 4 y + x^{2} + y^{2}

in the form of the standard circle equation

(x - 3)^{2} + (y - (- 2))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (3, - 2), r = 4

(x + 2)^{2} + (y + 9)^{2} = 70

x^{2} + y^{2} - 8 x - 6 y = 20

x^{2} + y^{2} - 6 x + 6 y + 17 = 0

x^{2} + y^{2} - 40 x + 144 = 0

x^{2} + (y + 6)^{2} = \frac{3}{4}

What is 3=-6x+4y+x^2+y^2 ?
The solution to 3=-6x+4y+x^2+y^2 is Circle with (a,b)=(3,-2),r=4