What is x^{(2)}+y^{(2)}-4=0 ?

The solution to x^{(2)}+y^{(2)}-4=0 is Circle with (a,b)=(0,0),r=2

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x^{(2)}+y^{(2)}-4=0

x^{(2)} + y^{(2)} - 4 = 0

(a, b) = (0, 0), r = 2

Solution steps

x^{2} + y^{2} - 4 = 0

Rewrite

x^{2} + y^{2} - 4 = 0

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 2

x^{2} + y^{2} + 42 x + 84 y + 65 = 0

(2 x - 1)^{2} + (2 y - 1)^{2} = 1

x^{2} - 14 x + y^{2} + 12 y = 36

x^{2} + y^{2} - 8 x - 12 y + 48 = 0

9 - x^{2} - y^{2} > 0

What is x^{(2)}+y^{(2)}-4=0 ?
The solution to x^{(2)}+y^{(2)}-4=0 is Circle with (a,b)=(0,0),r=2