What is 0=2-x^2-y^2 ?

The solution to 0=2-x^2-y^2 is Circle with (a,b)=(0,0),r=sqrt(2)

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0=2-x^2-y^2

0 = 2 - x^{2} - y^{2}

(a, b) = (0, 0), r = 2

Solution steps

0 = 2 - x^{2} - y^{2}

Rewrite

0 = 2 - x^{2} - y^{2}

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = (2)^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 2

y^{2} = 5 x - x^{2}

(x - 6)^{2} + (y - 2)^{2} = 36

x^{2} + y^{2} - 8 x - 3 y + 11 = 0

x^{2} + y^{2} = 1 3^{2}

(x - 3)^{2} + (y + 7)^{2} - 25 = 0

What is 0=2-x^2-y^2 ?
The solution to 0=2-x^2-y^2 is Circle with (a,b)=(0,0),r=sqrt(2)