What is 3x^2+3y^2-18x+6y+2=0 ?

The solution to 3x^2+3y^2-18x+6y+2=0 is Circle with (a,b)=(3,-1),r=(2sqrt(7))/(sqrt(3))

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3x^2+3y^2-18x+6y+2=0

3 x^{2} + 3 y^{2} - 18 x + 6 y + 2 = 0

(a, b) = (3, - 1), r = \frac{2 7}{3}

Solution steps

3 x^{2} + 3 y^{2} - 18 x + 6 y + 2 = 0

Rewrite

3 x^{2} + 3 y^{2} - 18 x + 6 y + 2 = 0

in the form of the standard circle equation

(x - 3)^{2} + (y - (- 1))^{2} = (\frac{2 7}{3})^{2}

Therefore the circle properties are:

(a, b) = (3, - 1), r = \frac{2 7}{3}

\frac{4 ( x + \frac{5}{2} ) ^{2}}{45} + \frac{4 ( y - 2 ) ^{2}}{45} = 1

x^{2} + (y - 1)^{2} = 2

x^{2} + (y - 1)^{2} = 7

x^{2} + (y + 5)^{2} = 61

x^{2} - 4 x + y^{2} - 6 y + 8 = 0

What is 3x^2+3y^2-18x+6y+2=0 ?
The solution to 3x^2+3y^2-18x+6y+2=0 is Circle with (a,b)=(3,-1),r=(2sqrt(7))/(sqrt(3))