What is ((x-1)^2+y^2)/2 =1 ?

The solution to ((x-1)^2+y^2)/2 =1 is Circle with (a,b)=(1,0),r=sqrt(2)

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((x-1)^2+y^2)/2 =1

\frac{( x - 1 ) ^{2} + y ^{2}}{2} = 1

(a, b) = (1, 0), r = 2

Solution steps

\frac{( x - 1 ) ^{2} + y ^{2}}{2} = 1

Rewrite

\frac{( x - 1 ) ^{2} + y ^{2}}{2} = 1

in the form of the standard circle equation

(x - 1)^{2} + (y - 0)^{2} = (2)^{2}

Therefore the circle properties are:

(a, b) = (1, 0), r = 2

2 x^{2} + 3 x + 2 y^{2} + 7 y = 57.75

x^{2} + y^{2} - 4 x + 8 y = 0

(x - (- 1))^{2} + (y - 3)^{2} = (3)^{2}

(x - 6)^{2} + (y + 5)^{2} = 4^{2}

x^{2} + y^{2} - 2 x + 6 y - 90 = 0

What is ((x-1)^2+y^2)/2 =1 ?
The solution to ((x-1)^2+y^2)/2 =1 is Circle with (a,b)=(1,0),r=sqrt(2)