What is x^2-2x+y^2-15=0 ?

The solution to x^2-2x+y^2-15=0 is Circle with (a,b)=(1,0),r=4

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x^2-2x+y^2-15=0

x^{2} - 2 x + y^{2} - 15 = 0

(a, b) = (1, 0), r = 4

Solution steps

x^{2} - 2 x + y^{2} - 15 = 0

Rewrite

x^{2} - 2 x + y^{2} - 15 = 0

in the form of the standard circle equation

(x - 1)^{2} + (y - 0)^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (1, 0), r = 4

(x - (- 1))^{2} + (y - 5)^{2} = 4

2 x^{2} + 3 x + 2 y^{2} + 7 y = 52.75

(x - 5)^{2} + (y - 2)^{2} = 49

(x - 15)^{2} + [y - (- 20)]^{2} = (9)^{2}

25 = (x + 7)^{2} + (y + 2)^{2}

What is x^2-2x+y^2-15=0 ?
The solution to x^2-2x+y^2-15=0 is Circle with (a,b)=(1,0),r=4